Habis dibagi 3

Ada soal dari Mella Camelia, dan diselesaikan oleh Ashfaq. . Mohon maaf jika ada bahasa inggris yang salah. Karena sobat soulmate semuanya kan masih belajar.

 

Mella Camelia

Sambil nunggu waktu berbuka😀 ..

Find all the positive integers n such that (n.2^n)+1 is divisible by 3

Ashfaq Ahmad

-2p-1+1 =0 mod 3
2q+1 =0 mod 3 hehe

 

Mella Camelia

What are the values of n?😀

 

Ashfaq Ahmad

n=6x+1 , 2.4^y

 

Mella Camelia

Still dont understand😦 .. . why do u put x and y?

 

Ashfaq Ahmad

2 = -1 mod 3
now 2^n either be 1 mod 3 if n is even . Or -1 if n is odd

 

Ashfaq Ahmad

At first case p =3x
and in second case q= 4^n

 

Mella Camelia

Oke, i got it. Thanks bro!🙂

 

Ashfaq Ahmad

Yo sis ……

Mella Camelia

But, i’ve found
if n=odd —> n=6p+1 (same w/ u)
and if n=even —> n=6p+2

 

Ashfaq Ahmad

Oh that’s great ……😦 mistake …..

 

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Tentang msihabudin

Just a crazy people
Pos ini dipublikasikan di SOUL-MATE-MATIKA dan tag . Tandai permalink.

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