Logaritma 1

Putri Princezna
Jika {}^2log \, a + {}^2log \, b = 12 dan 3 . {}^2log \, a- {}^2log \, b = 4,
maka a + b = \cdot

 

Purie Astagraha
{}^2log \, a= x
{}^2log \, b= y
{}^2log \, a + {}^2log \, b = 12 \to x+y=12
3 . {}^2log \, a- {}^2log \, b = 4 \to 3x-y=4
x= 4 \to a= 2^4
y= 8 \to b= 2^8
x+y= 2^4+2^8

Rusli Gustiono
hmmmm…………
{}^2log \, ab = 12 dan {}^2log \, \dfrac{a^3}{b} = 4
\dfrac{a^3}{b} = 2^4 \to a^3 =(2^4) b
ab=2^{12} \to a^3 . b^3 = 2^{36}
(2^4)b . b^3 = 2^{36} \to b^4 = 2^{32}
b = 2^8
a . 2^8 = 2^{12} \to a = 2^4
a + b =16 + 256
a + b = 272

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Tentang msihabudin

Just a crazy people
Pos ini dipublikasikan di SOUL-MATE-MATIKA. Tandai permalink.

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